Cambridge Cambridge International AS-Level Science

Cambridge Cambridge International AS-Level Science Learning Path

Detailed syllabus unit mapping, custom lesson objectives, required laboratory practical guides, and assessment MCQ checklists.

First half of advanced syllabus. Covers kinematics vectors, chemical enthalpies, orbital hybridization, and basic macromolecular cellular transport.

Lesson Plans & Objectives

Equations of Motion60 min

Derive the four SUVAT equations for uniform acceleration.
Resolve vectors into vertical and horizontal components.

Suggested Practical Activities

Determining acceleration of free fall (g) using electromagnets and light gates

Revision Notes

SUVAT equations: v = u + at, s = ut + 0.5at², v² = u² + 2as, s = 0.5(u+v)t.
Projectiles follow parabolic paths, where horizontal velocity is constant (neglecting drag).

CAIE Worked Examples & Mark Scheme Breakdown

Example 1: Projectile Range & Flight TimeCAIE Step-by-Step

A ball is launched from ground level at 25 m/s at an angle of 30° above horizontal. Calculate its total flight time before returning to ground level (g = 9.81 m/s²).

Step 1: Calculate initial vertical velocity component uyuy = 25 × sin(30°) = 25 × 0.5 = 12.5 m/s

Step 2: Use v = u + at for vertical ascent to apex0 = 12.5 - 9.81 × t_up → t_up = 12.5 / 9.81 = 1.274 s

Step 3: Double time for total flightt_total = 2 × 1.274 = 2.55 s

Final CAIE Answer:2.55 seconds

Example 2: Work Done & Inclined ResistanceCAIE Step-by-Step

A block of mass 4.0 kg slides 5.0 m down a plane inclined at 30° to horizontal. Friction force along plane is 6.0 N. Calculate net kinetic energy gained at bottom.

Step 1: Calculate vertical height hh = 5.0 × sin(30°) = 2.5 m

Step 2: Calculate initial potential energy EpEp = mgh = 4.0 × 9.81 × 2.5 = 98.1 J

Step 3: Calculate work done against friction W_fW_f = friction × distance = 6.0 × 5.0 = 30.0 J

Step 4: Subtract energy lost to find EkEk = 98.1 - 30.0 = 68.1 J

Final CAIE Answer:68.1 J

Example 3: Young Modulus DeterminationCAIE Step-by-Step

A metal wire of length 2.0 m and cross-sectional area 1.5 × 10⁻⁶ m² extends by 1.2 mm under a load of 180 N. Calculate the Young Modulus E of the wire.

Step 1: Calculate Stress σσ = Force / Area = 180 / (1.5 × 10⁻⁶) = 1.2 × 10⁸ Pa

Step 2: Calculate Strain εε = ΔL / L = (1.2 × 10⁻³ m) / 2.0 m = 6.0 × 10⁻⁴

Step 3: Compute Young Modulus E = σ / εE = (1.2 × 10⁸) / (6.0 × 10⁻⁴) = 2.0 × 10¹¹ Pa (200 GPa)

Final CAIE Answer:2.0 × 10¹¹ Pa (200 GPa)

Example 4: Enthalpy Change of Neutralization (Hess Law)CAIE Step-by-Step

In a calorimeter, 50.0 cm³ of 1.0 mol/dm³ HCl reacts with 50.0 cm³ of 1.0 mol/dm³ NaOH. Temperature increases by 6.8°C. Calculate ΔH per mole of water formed (c = 4.18 J/g·°C, density = 1.0 g/cm³).

Step 1: Calculate total mass and heat released qm = 100 g; q = m·c·ΔT = 100 × 4.18 × 6.8 = 2842.4 J

Step 2: Calculate moles of limiting reactantn = c × V = 1.0 × (50/1000) = 0.050 moles

Step 3: Calculate ΔH in kJ/molΔH = -(2.8424 kJ / 0.050 mol) = -56.8 kJ/mol

Final CAIE Answer:-56.8 kJ/mol

Example 5: Conservation of Momentum in 1D CollisionCAIE Step-by-Step

Trolley A (mass 2.0 kg) moving at 6.0 m/s collides with stationary Trolley B (mass 1.0 kg). They stick together after collision. Calculate their common final velocity.

Step 1: State momentum conservationmA·uA + mB·uB = (mA + mB)·v

Step 2: Substitute values(2.0 × 6.0) + (1.0 × 0) = (2.0 + 1.0)·v → 12.0 = 3.0·v

Step 3: Calculate vv = 12.0 / 3.0 = 4.0 m/s

Final CAIE Answer:4.0 m/s

Loading NexProTools...

Preparing interactive calculation engine

Cambridge Cambridge International AS-Level Science Learning Path

AS Physics: Kinematics & Mechanics

Lesson Plans & Objectives

Suggested Practical Activities

Revision Notes

CAIE Worked Examples & Mark Scheme Breakdown

Cambridge Cambridge International AS-Level Science Learning Path

AS Physics: Kinematics & Mechanics

Lesson Plans & Objectives

Suggested Practical Activities

Revision Notes

CAIE Worked Examples & Mark Scheme Breakdown